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Dear Antreas,
[APH]:
The circles (A,R), (B,R), (C,R) intersect the extensions of the
triangle sides as in the figure: (with slight change of notations)
Ba Ca
\ /
\ /
\ /
\ /
\/ A
/\
/ \
/ \
/ \
/ \
/ \
Ab---------B------------C----------Ac
/ \
/ \
/ \
/ \
Cb Bc
The radical center of the three circles ABaCa, BCbAb, and CAcBc
is the point
(a^2(a^2(b^2+c^2)-b^2c^2))/(2a^2-(2b^2-bc+2c^2)): ... : ...)
much more complicated than the previous one!
Best regards.
Sincerely,
Paul Yiu
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