Σάββατο 19 Οκτωβρίου 2019

HYACINTHOS 2348

  • Dear Antreas,

    [APH]:
    The circles (A,R), (B,R), (C,R) intersect the extensions of the
    triangle sides as in the figure: (with slight change of notations)



    Ba Ca
    \ /
    \ /
    \ /
    \ /
    \/ A
    /\
    / \
    / \
    / \
    / \
    / \
    Ab---------B------------C----------Ac
    / \
    / \
    / \
    / \
    Cb Bc


    The radical center of the three circles ABaCa, BCbAb, and CAcBc
    is the point

    (a^2(a^2(b^2+c^2)-b^2c^2))/(2a^2-(2b^2-bc+2c^2)): ... : ...)

    much more complicated than the previous one!

    Best regards.
    Sincerely,
    Paul Yiu


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