#1427
Dear Members!
Let ABC be a triangle. Point P is on it's circumcircle. Tangents at P to incircle of ABC intersect incircle and circumcircle in four points - let X_{P} be the intersection of it's diagonals. Then X_{P} (where P lies on circumcircle) lies on circle which contains Gergonne point of ABC and it's center in 6,9,13 is 1.084338...
Best regards,
Dominik Burek
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#1430
Dear Dominik, nice circle indeed!
I find that your circle has the point X1159 as center, and radius r (R - 2 r)/(4 R + r).
Best regards,
Francisco Javier.
I find that your circle has the point X1159 as center, and radius r (R - 2 r)/(4 R + r).
Best regards,
Francisco Javier.
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