Πέμπτη 31 Οκτωβρίου 2019

ADGEOM 3881 * ADGEOM 3884

#3881
 
Dear geometers,
 
Let S be the symmedian point ò ABC.
 
S' is isotomic conjugate of S wrt ABC.
 
A'B'C' is cevian triangle of S' wrt ABC.
 
S* is isogonal conjugate of S wrt A'B'C'.
 
Then S* lies on Euler line of ABC. 
 
Which is this point ?
 
Best regards,
Tran Quang Hung.
 
 
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#3884
 
The first barycentric coordinate of  the point S* on Euler line is

a^12-a^8 (b^4+b^2 c^2+c^4)+2 a^6 (b^6+c^6)+a^4 (b^8+b^6 c^2-2 b^4 c^4+b^2 c^6+c^8)-2 a^2 (b^10+b^6 c^4+b^4 c^6+c^10)-(b^4-c^4)^2 (b^4+c^4)

 (6 - 9 - 13) - search numbers (5.07596651974519, 4.19305606900199, -1.60497426728401).
 
 Angel Montesdeoca
 
 

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