#3881
Dear geometers,
Let S be the symmedian point ò ABC.
S' is isotomic conjugate of S wrt ABC.
A'B'C' is cevian triangle of S' wrt ABC.
S* is isogonal conjugate of S wrt A'B'C'.
Then S* lies on Euler line of ABC.
Which is this point ?
Best regards,
Tran Quang Hung.
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#3884
The first barycentric coordinate of the point S* on Euler line is
a^12-a^8 (b^4+b^2 c^2+c^4)+2 a^6 (b^6+c^6)+a^4 (b^8+b^6 c^2-2 b^4 c^4+b^2 c^6+c^8)-2 a^2 (b^10+b^6 c^4+b^4 c^6+c^10)-(b^4-c^4)^2 (b^4+c^4)
(6 - 9 - 13) - search numbers (5.07596651974519, 4.19305606900199, -1.60497426728401).
Angel Montesdeoca
a^12-a^8 (b^4+b^2 c^2+c^4)+2 a^6 (b^6+c^6)+a^4 (b^8+b^6 c^2-2 b^4 c^4+b^2 c^6+c^8)-2 a^2 (b^10+b^6 c^4+b^4 c^6+c^10)-(b^4-c^4)^2 (b^4+c^4)
(6 - 9 - 13) - search numbers (5.07596651974519, 4.19305606900199, -1.60497426728401).
Angel Montesdeoca
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