#2342
Dear Dr. Paul Yiu, Dr. Kimberling and all Geometers,
Let ABC be a triangle, Let (W) be the circle through X(3),X(110) and X(4240) in ETC. I found 7 points also lie on (W) as follows:
Let the Euler line of ABC meets the sidelines BC,CA,AB at A0,B0,C0. Six points X(3), X(110) of three triangles AB0C0, BA0C0, CB0A0 also lie on (W). The circumcenter X(3) of Paralogic triangle whose perpectrix is the Euler line of ABC also lie on (W). So 10 points lie on this circle.
Please see the file attachment.
I am thank to You very much.
Best regards
Sincerely
Dao Thanh Oai
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#2343
Dear Dr. Paul Yiu, Dr. Kimberling and all Geometers,
Let O = circumcenter of ABC
Let O'=X(3) of Paralogic triangle whose perpectrix is the Euler line of ABC also lie on (W). So 10 points lie on this circle. OO' be the diameter of this circle
Best regards
Sincerely
Dao Thanh Oai
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#2344
Dear Dao Thanh Oai,
The circumcenter of the triangle A1B1C1 is X(5502).
The circle (W) intersects the circumcircle in X(110) and X(1304).
X(4240)=(Euler line of ABC)/\ X(107)X(110) also lie on (W).
Best regards,
Angel Montesdeoca
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