Dear friends
If A', B', C' are the incenters of triangles IBC, ICA, IAB
I = Incenter of ABC
then I think that the triangles ABC, A'B'C' are perspective
at P = (1/(cotA-cot(A/4)) : . . : . . )
with search 6_9_13 number 44.3018615934
and this point is not in ETC.
Am I right?
Best regards
Nikos Dergiades
Δεν υπάρχουν σχόλια:
Δημοσίευση σχολίου