ADGEOM 2697 * ADGEOM 2698

#2697

 

[Tran Quang Hung]:

 

Dear geometers,

Let ABC be a triangle.

Perpendicular bisector of BC cuts CA,AB at Ab,Ac. Let da be perpendicular bisector of segment AbAc. Simiarlaly, we have the lines db,dc.

Then, triangle bound by lines da,db,dc has nine point circle which is tangent to circumcircle of triangle ABC.

Please, the tangent point is new ?

Best regards,

Tran Quang Hung.

 

#2698

[Paul Yiu]:

Dear QH,

 

[TQH]:  Let ABC be a triangle.

Perpendicular bisector of BC cuts CA,AB at Ab,Ac. Let da be perpendicular bisector of segment AbAc. Simiarlaly, we have the lines db,dc.Then, triangle bound by lines da,db,dc has nine point circle which is tangent to circumcircle of triangle ABC.

 

*** Euler reflection point X(110).

 

Best regards

Sincerely

Paul Yiu