1 and 2: Hyacinthos 28463
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Let ABC be a triangle and P a point on the Euler line (such that PO/OH = t : number?).
3. Denote:
N1, N2, N3 = the NPC centers of GBC, GCA, GAB, resp.
Aa, Ab, Ac = the midpoints of AN1, BN1, CN1, resp.
Ba, Bb, Bc = the midpoints of AN2, BN2, CN2, resp.
Ca, Cb, Cc = the midpoints of AN3, BN3, CN3, resp.
Pa, Pb, Pc = same to P points of the triangles AaAbAc, BaBbBc, CaCbCc, resp.
(ie Pa lies on the Euler line of AaAbAc such that PaOa / OaHa = t and similarly Pb, Pc)
Conjecture:
The centroid of PaPbPc lies on the Euler line of ABC.
Which is it in terms of t?
Your conjecture is true for any t.
If Gp is the centroid of PaPbPc, then
Gp(t) = (-2+4*t)*a^4-(b^2+c^2)*(-3+2*t)*a^2+(b^2-c^2)^2*(-2*t-1) : : (barys)
= midpoint of P and N
ie, OGp/OH = (2*t+1)/4
ETC pairs (P,Gp(P)):
(2,547), (3,140), (4,546), (20,548), (21,10021), (26,13383), (140,3628), (376,12100), (381,5066), (382,3853), (546,3850), (547,10109), (548,3530), (549,2), (632,1656), (1656,12812), (1657,12103), (1658,10020), (2070,10096), (3530,16239), (3543,12101), (3545,14892), (3651,11277), (3830,14893), (3843,3859), (3845,381), (3850,12811), (3853,3861), (3857,3851), (3858,3091), (3861,3856), (5066,11737), (5428,6675), (5499,442), (5500,10286), (5501,15957), (6644,6677), (7502,6676), (7575,468), (7715,13861), (8703,549), (10126,10289), (10127,10128), (10154,10201), (10205,10126), (10212,12043), (10226,5498), (10285,5501), (10295,18571), (11001,15691), (11250,23336), (11539,15699), (11563,403), (11819,6756), (12100,10124), (12107,18282), (13163,23409), (13371,10224), (13631,13362), (14891,11540), (14893,3860), (15122,5159), (15327,12056), (15331,10125), (15334,12057), (15681,15690), (15686,8703), (15687,3845), (15690,14891), (15691,15759), (15699,5055), (15704,550), (15711,15694), (15712,632), (15714,15713), (15761,13406), (16160,6841), (16340,3154), (17504,11539), (18282,12010), (18572,10297), (19710,376), (20030,19940), (20120,20030), (23335,13371)
Some others:
Gp( X(22) ) = midpoint of X(5) and X(22)
= 2*a^10-5*(b^2+c^2)*a^8+2*(b^2-c^2)^2*a^6+2*(b^2+c^2)*(2*b^4+b^2*c^2+2*c^4)*a^4-2*(b^2-c^2)^2*(2*b^4+b^2*c^2+2*c^4)*a^2+(b^4-c^4)*(b^2-c^2)^3 : : (barys)
= as a point on the Euler line, this center has Shinagawa coefficients (-5*E-12*F, 7*E+4*F)
= on lines: {2, 3}, {523, 11619}, {2781, 10272}, {3564, 19127}, {3589, 13364}, {6689, 13598}, {8717, 23329}, {9019, 13451}, {9820, 10627}, {11591, 16252}, {13391, 23292}
= midpoint of X(i) and X(j) for these {i,j}: {5, 22}, {6676, 16618}, {7502, 15760}
= reflection of X(i) in X(j) for these (i,j): (140, 6676), (427, 3628), (18570, 3530)
= complement of the complement of X(12083)
= {X(i),X(j)}-harmonic conjugate of X(k) for these (i,j,k): (3, 10020, 140), (140, 10096, 6677), (550, 7542, 23336), (2937, 13160, 11819), (3530, 16238, 140), (3530, 18282, 16238), (3547, 10565, 18420), (6636, 7552, 2072), (6677, 13383, 10096), (7517, 7558, 5), (7542, 23336, 140), (10125, 16196, 140), (10565, 18420, 26), (13383, 16197, 140)
= [ -11.9052889476672700, -12.7434024177163300, 17.9577687469421200 ]
Gp( X(23) ) = midpoint of X(5) and X(23)
= 2*a^10-5*(b^2+c^2)*a^8+2*(b^4-b^2*c^2+c^4)*a^6+(b^2+c^2)*(4*b^4-5*b^2*c^2+4*c^4)*a^4-(b^2-c^2)^2*(4*b^4-3*b^2*c^2+4*c^4)*a^2+(b^4-c^4)*(b^2-c^2)^3 : : (barys)
= 2*X(12002)-3*X(13446), 3*X(14643)+X(15107)
= As a point on the Euler line, this center has Shinagawa coefficients (-3*E-24*F, 17*E+8*F)
= on lines: {2, 3}, {511, 10272}, {523, 6140}, {1154, 16534}, {1533, 12041}, {5305, 16308}, {5446, 15806}, {5462, 20193}, {7286, 15325}, {8157, 24305}, {8254, 10110}, {8705, 18583}, {11649, 13451}, {12002, 13446}, {14643, 15107}, {21660, 22051}
= midpoint of X(i) and X(j) for these {i,j}: {5, 23}, {468, 16619}, {550, 18325}, {1533, 12041}, {2070, 11563}, {7575, 11799}
= reflection of X(i) in X(j) for these (i,j): (3, 22249), (140, 468), (548, 18571), (858, 3628), (18323, 3861), (18572, 3850)
= orthoptic circle of Steiner inellipse-inverse-of X(7533)
= {X(i),X(j)}-harmonic conjugate of X(k) for these (i,j,k): (4, 18282, 140), (23, 186, 2937), (140, 10096, 468), (186, 18325, 550), (403, 18572, 3850), (1656, 5899, 5189), (2070, 18378, 23), (7426, 11799, 7575), (7495, 7574, 15122), (7545, 7552, 5)
= [ -1.2503473881203710, -2.1165688630372750, 5.6830647969888210 ]
César Lozada
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