Antreas P. Hatzipolakis
Let ABC be a triangle, L,La,Lb,Lc the Euler lines of ABC, IBC, ICA, IAB, resp. (concurrent at S) and Oa,Ob,Oc the circumcenters of IBC, ICA, IAB, resp.
Denote:
Ab, Ac = the orthogonal projections of Oa on Lb,Lc, resp.
Bc, Ba = the orthogonal projections of Ob on Lc,La, resp.
Ca, Cb = the orthogonal projections of Oc on La,Lb, resp.
O1, O2, O3 = the circumcenters of OaAbAc, ObBcBa, OcCaCb, resp.
1. The triangles ABC, O1O2O3 are perspective.
2. The circumcenter of O1O2O3 is on the line L.
True??
Figure
http://anthrakitis.blogspot.gr/2013/02/euler-lines-circumcircles.html
APH
Τρίτη 22 Οκτωβρίου 2019
HYACINTHOS 21509
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