[Antreas P. Hatzipolakis]:
Let ABC be a triangle and A'B'C' the pedal triangle of I.
Denote:
Denote:
A", B", C" = the antipodes of A', B', C' in the incircle, resp.
A* = AA" /\ BC
B* = BB" /\ CA
C* = CC" /\ AB
MaMbMc = the medial triangle of A"B"C"
M1, M2, M3 = the midpoints of AA*, BB*, CC*, resp.
B* = BB" /\ CA
C* = CC" /\ AB
MaMbMc = the medial triangle of A"B"C"
M1, M2, M3 = the midpoints of AA*, BB*, CC*, resp.
The triangles M1M2M3, MaMbMc are circumcyclologic
ie the circumcircles of M1MbMc, M2McMa, M3MaMb and M1M2M3 are concurrent
the circumcircles of MaM2M3, MbM3M1, McM1M2 and MaMbMc are concurrent.
the circumcircles of MaM2M3, MbM3M1, McM1M2 and MaMbMc are concurrent.
Cyclologic centers?
[Angel Montesdeoca[:
*** Cyclologic center of M1M2M3 wrt MaMbMc is X(3035) = complement of Feuerbach point.
*** Cyclologic center of MaMbMc wrt M1M2M3 is
V = a (a^5 (b+c)
-a^4 (b^2+6 b c+c^2)
+a^3 (-2 b^3+7 b^2 c+7 b c^2-2 c^3)
+a (b-c)^2 (b^3-6 b^2 c-6 b c^2+c^3)
+a^2 (2 b^4+5 b^3 c-18 b^2 c^2+5 b c^3+2 c^4)
-(b^2-c^2)^2 (b^2-b c+c^2)) : ... : ....
V is the midpoint of X(i) and X(j), for these {i, j}: {1,12758}, {11,3057}, {10284,12619}.
V is the reflection of X(i) in X(j), for these {i, j}: {5083,1}, {5836,6667}, {12736,1387}, {14740,960}.
(6 - 9 - 13) - search numbers of W: (2.74701291332711, 3.01069105643210, 0.288487790534261)
Angel Montesdeoca
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