[Antreas P. Hatzipolakis]:
Let ABC be a triangle and A'B'C' the pedal triangle of O.
Denote:
A", B", C" points on OA', OB', OC', resp. such that:
A"O/A"A' = B"O/B"B' = C"O/C"C' = t
Ab, Ac = the orthogonal projections of A" on OB, OC, resp.
Bc, Ba = the orthogonal projections of B" on OC, OA, resp.
Ca, Cb = the orthogonal projections of C" on OA, OB, resp.
A*B*C* = the triangle bounded by AbAc, BcBa, CaCb.
ABC, A*B*C* are homothetic.
Which is the locus of the homothetic center as t varies?
[César Lozada]:
Locus = Line through ETC’s:
{ 3, 49, 155, 184, 185, 283, 394, 1092, 1147, 1181, 1204, 1216, 1437, 1790, 1800, 1801, 1819, 3167, 3292, 3796, 3917, 5406, 5407, 5408, 5409, 5447, 5562, 7689, 8913, 9703, 9704, 9720, 9908, 10132, 10133, 10605, 10670, 10674, 10984}
= polar trilinear of X(4558)
= isogonal of the rectangular hyperbola CyclicSum[b*c*(SB-SC)*SB*SC*v* w)]=0, with center=X(136), perspector=X(2501) and passing through ETC’s: 4, 93, 225, 254, 264, 393, 847, 1093, 1105, 1179, 1217, 1300, 1826, 6344, 6526, 6531, 8737, 8738, 8741, 8742, 8801, 8884
If the homothetic center is Z(t), then
OZ(t) = t*(7*R^2-2*SW)/(2*(2*R^2+(3*R^ 2-SW)*t))*X(3)X(49)
César Lozada
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