HYACINTHOS 24369

[Antreas P. Hatzipolakis]:

Let ABC be a triangle and A'B'C' the antipedal triangle of I (excentral triangle).
A*, B*, C* = X(110) of A'BC, B'CA, C'AB.
The circles with diameters AA*, BB*, CC* and the circumcircle of ABC are concurrent.
Which is the point of concurrence?

APH

***  X(2222)

Angel Montesdeoca