HYACINTHOS 19707

Dear Hyacinthists,
this is a conjecture:
the Spieker's point of ABC is the center of perspective of the medial triangle of ABC with the radical triangle of ABC.
The radical triangle of ABC is determined by the intersection of the radical axes of the circumcircle of ABC with the resp. excircles of ABC.
Please, can some one confirms or not this result.
Sincerely
Jean-Louis Ayme