Dear Hyacinthians,
the following proposition can easily be proven synthetically:
The triangle formed by the radical axes of the Bevan circle and the
excircles is homothetic with ABC
The perspector turns out to be very simple
P = (a.(s.s - b.c) : b.(s.s - c.a) : c.(s.s - a.b) )
From its coordinates we see immediately that it lies on the line
through the incenter and the centroid
The triangle formed by the radical axes of the Bevan circle and the
excircles is also homothetic with ABC and the perspector is the
Spieker center
Greetings from Bruges
Eric Danneels
the following proposition can easily be proven synthetically:
The triangle formed by the radical axes of the Bevan circle and the
excircles is homothetic with ABC
The perspector turns out to be very simple
P = (a.(s.s - b.c) : b.(s.s - c.a) : c.(s.s - a.b) )
From its coordinates we see immediately that it lies on the line
through the incenter and the centroid
The triangle formed by the radical axes of the Bevan circle and the
excircles is also homothetic with ABC and the perspector is the
Spieker center
Greetings from Bruges
Eric Danneels
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